-20x^2-35x+10=0

Solution for -20x^2-35x+10=0 equation:

-20x^2-35x+10=0

a = -20; b = -35; c = +10;
Δ = b2-4ac
Δ = -352-4·(-20)·10
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-45}{2*-20}=\frac{-10}{-40}
=1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+45}{2*-20}=\frac{80}{-40}
=-2
$